如何从AWT / SWING中的相同文本字段输入两位数字(How to enter two digits from same textfield in AWT/SWING)

我创建了一个简单的计算器，在其中我在两个不同的文本字段中输入两个操作数，并且它运行良好。但是我需要从同一个文本域中获取两个输入。我应该做什么改变？

import java.awt.*; import java.awt.event.*; import javax.swing.*; class Calculation_ActionEvent extends JFrame implements ActionListener { JFrame f; JLabel l; JTextField tf1, tf2, tf3; JButton b1, b2, b3, b4 ,b5, b6; Calculation_ActionEvent(String s) { f = new JFrame("Calculation"); f.setLayout(null); l = new JLabel("Enter two numbers : "); tf1 = new JTextField(); tf2 = new JTextField(); tf3 = new JTextField(); b1 = new JButton("+"); b2 = new JButton("-"); b3 = new JButton("*"); b4 = new JButton("/"); b5 = new JButton("equals"); b6 = new JButton("C"); f.add(l); f.add(tf1); f.add(tf2); f.add(tf3); f.add(b1); f.add(b2); f.add(b3); f.add(b4); f.add(b5); f.add(b6); tf1.setBounds(180,100,50,30); tf2.setBounds(320,100,50,30); tf3.setBounds(250,420,50,30); b1.setBounds(250,180,50,30); b2.setBounds(350,260,50,30); b3.setBounds(150,260,50,30); b4.setBounds(250,340,50,30); b5.setBounds(230,260,90,30); b6.setBounds(250,100,50,30); b1.addActionListener(this); b2.addActionListener(this); b3.addActionListener(this); b4.addActionListener(this); //b5.addActionListener(this); b6.addActionListener(this); f.setSize(550,550); f.setVisible(true); } public void actionPerformed(ActionEvent e) { int num1= Integer.parseInt(tf1.getText()); int num2= Integer.parseInt(tf2.getText()); String s1 = e.getActionCommand(); if(s1.equals("C")) { tf1.setText("0"); tf2.setText("0"); tf3.setText("0"); } else { if(s1=="+") { tf3.setText(String.valueOf(num1+num2)); } if(s1=="-") { tf3.setText(String.valueOf(num1-num2)); } if(s1=="*") { tf3.setText(String.valueOf(num1*num2)); } if(s1=="/") { tf3.setText(String.valueOf(num1/num2)); } } } public static void main(String... s) { new Calculation_ActionEvent("Calculation"); } }

I have created a Simple calculator in which I take inputs of two operands in two different textfields, and it is working good. But I need to take two inputs from same textfield. What changes should I make?

最满意答案

这是否就像你在找什么？我为你做了一个快速版本。

简单地说，我将最后一个运算符（ + ， - ， * ， / ）存储在一个String变量（ lastAction ）中， total为int 。当按下“等于”时，我计算总数并重置total变量和lastAction 。当按下一个操作符时，我改变总数，但将最后一个值保存在一个变量中。

package cf.pgmann.calc; import java.awt.event.ActionEvent; import java.awt.event.ActionListener; import javax.swing.JButton; import javax.swing.JFrame; import javax.swing.JLabel; import javax.swing.JTextField; class Calculation_ActionEvent extends JFrame implements ActionListener { JFrame f; JLabel l; JTextField tf1, tf3; JButton b1, b2, b3, b4, b5, b6; Calculation_ActionEvent(String s) { f = new JFrame(s); f.setLayout(null); l = new JLabel("Enter two numbers : "); tf1 = new JTextField(); // tf2 = new JTextField(); tf3 = new JTextField(); b1 = new JButton("+"); b2 = new JButton("-"); b3 = new JButton("*"); b4 = new JButton("/"); b5 = new JButton("equals"); b6 = new JButton("C"); f.add(l); f.add(tf1); f.add(tf3); f.add(b1); f.add(b2); f.add(b3); f.add(b4); f.add(b5); f.add(b6); tf1.setBounds(160, 100, 250, 30); // tf2.setBounds(320,100,50,30); tf3.setBounds(250, 420, 50, 30); b1.setBounds(250, 180, 50, 30); b2.setBounds(350, 260, 50, 30); b3.setBounds(150, 260, 50, 30); b4.setBounds(250, 340, 50, 30); b5.setBounds(230, 260, 90, 30); b6.setBounds(420, 100, 50, 30); b1.addActionListener(this); b2.addActionListener(this); b3.addActionListener(this); b4.addActionListener(this); b5.addActionListener(this); b6.addActionListener(this); f.setSize(550, 550); f.setVisible(true); } int total = 0; String lastAction = ""; public void actionPerformed(ActionEvent e) { int num = 0; try { num = Integer.parseInt(tf1.getText()); } catch(NumberFormatException ex) {} String s1 = e.getActionCommand(); if (s1.equals("C")) { tf1.setText(""); tf3.setText("0"); tf1.requestFocus(); total = 0; } else if (s1.equals("equals")) { tf3.setText(String.valueOf(calc(total, lastAction, num))); tf1.setText(""); tf1.requestFocus(); total = 0; } else { total = total==0 ? num : calc(total, lastAction, num); tf3.setText(String.valueOf(total)); tf1.setText(""); tf1.requestFocus(); lastAction = s1; } } private int calc(int num1, String action, int num2) { switch (action) { case "+": return num1 + num2; case "-": return num1 - num2; case "*": return num1 * num2; case "/": return num1 / num2; default: return num1; } } public static void main(String... s) { new Calculation_ActionEvent("Calculator"); } }

Would this be something like what you're looking for? I did a quick version for you.

Simply put, I store the last operator (+, -, *, /) in a String variable (lastAction), the total as an int. When "equals" is pressed, I work out the total and reset the total variable and lastAction. When an operator is pressed, I change the total but keep the last value in a variable.

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