我的人有分数,我想要一种有效的方法来查询给定用户是否在顶级X用户中。
# person.rb class Person scope :top_score, -> {order('score DESC')} scope :page_limit, -> { limit(10) } def self.in_top_score(id) top_score.page_limit.something_something_soemthign? end end以前在做:
user.id.in?(top_score.page_limit.pluck(:id))但我更愿意将此检查移至数据库,以防止数百/数千条记录的对象序列化。
Person.order('score DESC').select([:score, :id]).limit(1) Person Load (0.5ms) SELECT score, id FROM `people` ORDER BY score DESC LIMIT 1 => [#<Person id: "dxvrDy...", score: 35>]现在检查该列表中是否存在另一个用户^^
Person.order('score DESC').select([:score, :id]).limit(1).exists?({id: "c_Tvr6..."}) Person Exists (0.3ms) SELECT 1 AS one FROM `people` WHERE `people`.`id` = 'c_Tvr6...' LIMIT 1 => true返回true但应返回false
My people have scores and I'd like an efficient way to query if the given user is in the top X users.
# person.rb class Person scope :top_score, -> {order('score DESC')} scope :page_limit, -> { limit(10) } def self.in_top_score(id) top_score.page_limit.something_something_soemthign? end endpreviously was doing:
user.id.in?(top_score.page_limit.pluck(:id))but i'd prefer to move this check to the database to prevent the object serialization of hundreds/thousands of records.
Person.order('score DESC').select([:score, :id]).limit(1) Person Load (0.5ms) SELECT score, id FROM `people` ORDER BY score DESC LIMIT 1 => [#<Person id: "dxvrDy...", score: 35>]now to check if another user exists in that list^^
Person.order('score DESC').select([:score, :id]).limit(1).exists?({id: "c_Tvr6..."}) Person Exists (0.3ms) SELECT 1 AS one FROM `people` WHERE `people`.`id` = 'c_Tvr6...' LIMIT 1 => truereturns true but should return false
最满意答案
更新的答案
对不起,我的原始答案不正确。 ( exists?查询显然使用LIMIT 1并从page_limit范围覆盖LIMIT 10 ,并且显然也抛出了ORDER BY子句。完全错误!:-p)
那这个呢? 它有点不那么优雅,但这次我实际测试了答案:-p,它似乎按照需要工作。
def self.in_top_score?(id) where(id: id).where(id: Person.top_score.page_limit).exists? end这是我的测试(使用Rails 4.2.6)和它生成的SQL(使用子查询)的示例用法:
pry(main)> Person.in_top_score?(56) Person Exists (0.4ms) SELECT 1 AS one FROM "people" WHERE "people"."id" = $1 AND "people"."id" IN (SELECT "people"."id" FROM "people" ORDER BY "people"."score" DESC LIMIT 10) LIMIT 1 [["id", 56]] => false在我的测试中,与原始版本相比,这确实至少有一点性能提升。
原始答案
top_score.page_limit.exists?(user.id)http://apidock.com/rails/ActiveRecord/FinderMethods/exists%3F
updated answer
Sorry, my original answer was incorrect. (The exists? query evidently uses LIMIT 1 and overwrites the LIMIT 10 from the page_limit scope, and evidently throws out the ORDER BY clause, too. Totally wrong! :-p)
What about this? It's a little bit less elegant, but I actually tested the answer this time :-p, and it seems to work as desired.
def self.in_top_score?(id) where(id: id).where(id: Person.top_score.page_limit).exists? endHere's an example usage from my testing (using Rails 4.2.6) and the SQL it generates (which uses a subquery):
pry(main)> Person.in_top_score?(56) Person Exists (0.4ms) SELECT 1 AS one FROM "people" WHERE "people"."id" = $1 AND "people"."id" IN (SELECT "people"."id" FROM "people" ORDER BY "people"."score" DESC LIMIT 10) LIMIT 1 [["id", 56]] => falseIn my testing, this does indeed have at least a bit of a performance boost compared to your original version.
original answer
top_score.page_limit.exists?(user.id)http://apidock.com/rails/ActiveRecord/FinderMethods/exists%3F
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