在PHP中动态添加x天到日期(Dynamically adding x number of days to a date in PHP)

在PHP中动态添加x天到日期(Dynamically adding x number of days to a date in PHP)

我有一个场景，我必须添加x数字，如果天数包含日期的变量。 这个x将是动态的，无法猜到。

关于如何实现这一点的任何建议？

$ticket_created_on_date_time = '2016-08-31 09:55:01' $in_between_days = 2;

I have a scenario where I have to add x number if days to a variable containing date. This x will be dynamic and cannot be guessed.

Any suggestions on how I can implement this?

$ticket_created_on_date_time = '2016-08-31 09:55:01' $in_between_days = 2;

最满意答案

您可以使用数学和strtotime函数来获取过去/未来的日期。 就像是：

strtotime($ticket_created_on_date_time) + (86400 * $in_between_days)

（86400是几秒钟内）....或

strtotime($ticket_created_on_date_time . '+ ' . $in_between_days . ' days')

演示： https ： //eval.in/634187

You can use math and the strtotime function to get a date in the past/future. Something like:

strtotime($ticket_created_on_date_time) + (86400 * $in_between_days)

(86400 is one day in seconds) ....or

strtotime($ticket_created_on_date_time . '+ ' . $in_between_days . ' days')

Demo: https://eval.in/634187