在第x次提出错误并在此之后返回一个值(raise an error on the xth time and after that return a value)

在第x次提出错误并在此之后返回一个值(raise an error on the xth time and after that return a value)

我想使用rspec来模拟Flakey服务处理。

为此，我想让服务调用引发异常几次，并在这些时间之后返回实际值。

这可能与rspec？

我尝试过

allow(Service).to receive(:run).once.and_raise(MyError) allow(Service).to receive(:run).once.and_return(response)

但在第一次运行时它返回响应而不是错误

I want to use a rspec to simulate a flakey service handling.

For that, I want to make the service call raise an exception for a few times and after those times to return the real value.

Is this possible with rspec?

I tried with

allow(Service).to receive(:run).once.and_raise(MyError) allow(Service).to receive(:run).once.and_return(response)

but on the first run it returns the response and not the error

最满意答案

您可以使用响应的块实现完成此操作。

call_count = 0 allow(Service).to receive(:run) do call_count += 1 call_count < 3 ? raise(MyError) : response end

You can accomplish this with a block implementation for the response.

call_count = 0 allow(Service).to receive(:run) do call_count += 1 call_count < 3 ? raise(MyError) : response end