我为Azure APIM编写了一个简单的策略表达式,其中包含一个代码块表达式。 这有效:
@ {return“start”+ new Random()。Next()。ToString(); }
但是,这不起作用:
@ {return“start”+ new Random()。Next()。ToString()+“end”}
我尝试了第二个示例的几个变体,但无法让APIM策略管理器接受它。 APIM策略错误返回以下错误:
“第1行第21行中元素'log-to-eventhub'中的错误:代码块表达式必须用大括号括起来。”
但是,上面的表达式是大括号。 知道如何在上面的第二个例子中实现我想要做的事情吗?
I've written a simple policy expression for Azure APIM which includes a code block expression. This works:
@{ return "start" + new Random().Next().ToString(); }
However, this does not work:
@{ return "start" + new Random().Next().ToString() + "end" }
I tried several variations of the second example but was unable to get the APIM policy manager to accept it. The APIM policy error returns the following error:
"Error in element 'log-to-eventhub' on line 1, column 21: Code block expression must be enclosed in curly brackets."
However, the expression above is in curly brackets. Any idea how I can achieve what I'm trying to do in the second example above?
最满意答案
尝试将其重写为(注意末尾的分号):
@ {return“start”+ new Random()。Next()。ToString()+“end”; }
或(没有“返回”):
@ {“start”+ new Random()。Next()。ToString()+“end”}
Try rewriting it as (note semicolon at the end):
@{ return "start" + new Random().Next().ToString() + "end"; }
or (without "return"):
@{ "start" + new Random().Next().ToString() + "end" }
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